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leetcode array medium problems

Solution: if we get more examples, we could found the following rules, “aba”,”aba” return -1, 424. For simple questions, basic math and data structure can solve the problems. Or we can use two pointers. 1 min read. “[LeetCode]#1460. T(n) = max(T(n-1)+1, T(n-k)+1, …). 51.7%. Medium. The saving of time complexity is totally from the sorting algorithm. 39. GIT URL: Java Solution of Leet Code’s Squares of a Sorted Array problem. Environment: Python 3.8. Your algorithm should run in O(n) complexity. We can even speedup further by using binary search, the second loop we can use a binary search to make the time complexity O(logn), and the dp array used to save the maximum ans. T1: If you see in the problem that you can do comparison and it is always one type of satisfactory element is in ahead of the other, this could be resolved by two pointers (slower and faster). Implementing a serverless API proxy in 10 minutes, How to Convert JavaScript Classes to React’s useReducer Hook, How to autogenerate forms in React and Material-UI with MSON, Definitive guide for Nest.js guards and Passport, How to build a React project from scratch using Webpack 4 and Babel, Find duplicate problems: hashmap is leveraged as helper data structure. Like arrays, Linked List is a linear data structure. Follow. Solution: Another different problem, to count the number of the max subsequence. dict[0]=1. Solution, for this problem we just need to find see if any of the subproblems return true. Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: The sum of the entire nums array is guaranteed to fit within the 32-bit signed integer range. Apr 28, 2019. A New Way to Learn. Arrays can be used to store linear data of similar types, but arrays have following limitations. Move Zeroes, 121. If we use divide and conquer, sum the first half, and save a dictionary (counter), time complexity is O(2N²). For this problem, we need to understand it is not going to work with two for loops. Find all unique triplets in the array which gives the sum of zero. LeetCode. Given a string that consists of only uppercase English letters, you can replace any letter in the string with another letter at most k times. The longest repeating string we can by number of replacement = `length of string — max(numer of occurence of letter i), i=’A’ to ‘Z’. The majority element is the element that appears more than ⌊ n/2 ⌋ times. 49.6%. Sign in. For Linked List, we can only iterate over elements, for python code example: Two Pointers in Linked List (Fast-slow pointers). i,j start from 0,1 respectively. Note: when the while loop stops, is there operations you need? Array Problem is given an array, to ask you to meet a certain requirements. We recursively try call possible. Best Time to Buy and Sell Stock II (multiple transaction, accumulate sectional profit), 26, 27, 283. Now, we know we are doing dynamic programming, if we already know the ans(idx), meaning the max length from somewhere, we do not need to do it again. Given a binary array, find the maximum length of a contiguous subarray with equal number of 0 and 1. Given nums = [1, -1, 5, -2, 3], k = 3, return 4. Contest. Combination Sum, 416. Make Two Arrays Equal by Reversing Sub-arrays” is published by Fatboy Slim. To make problem a bit easier, all A, B, C, D have same length of N where 0 ≤ N ≤ 500. Then for 3, nodes 6,7 are its possible next steps. Example 2: Input: array = [0,1,2,4,2,1], target = 3. Example 1: Input: 2 Output: [0,1,1] Example 2: Input: 5 Output: [0,1,1,2,1,2] Solution: Return its length: 4. Solution: at first, use a Counter to save the whole set. Merge k Sorted Lists, 21. Mock. Note that there may be more than one LIS combination, it is only necessary for you to return the length. Container With Most Water (t2, move with greedy programming). ✍️A book in progress@https://github.com/liyin2015/Algorithms-and-Coding-Interviews. Trivially, any string is a subsequence of itself and an empty string is a subsequence of any string. which means every time we just set the dict[i]=current_idx,only if the key doesnt exist. This problem[1] asks us to sort an array of numbers into odd and even numbers. In this problem, you are given a sorted array, and should return a sorted array of the squares of the values in the array. I’v worked in Singapore as data scientist after graduation from Taiwan and currently I work in Amsterdam as machine learning engineer. Update: There are alternative ways to solve this issue without the use of separate arrays, I'm just wondering if this approach can work. In this process, we transfer from the combination problem to dynamic programming. Leetcode 1679: Max Number of K-Sum Pairs. 2). If we want the sum==k, sum(j,i)=sum(0,i)-sum(0,j) =k, when i=1, j=0. Write on Medium, #First, construct a head and point and record the head, (b) if( max_ending_here > max_so_far) #update the max. Leetcode: https://leetcode.com/problems/squares-of-a-sorted-array/ Construct Binary Tree from Inorder and Postorder Traversal. Usually, it can be solved with below techniques: Sorting: HashMap or HashSet: find duplicate, find intersections. Without this we detect cycle with the following code: Traverse linked list using two pointers. Problem Description: Given two string arrays word1 and word2, return true if the two arrays represent the same string, and false otherwise. we save prefix sum, at the same time, we check if we can find a sum(0,j) ==sum(0,i)-k, j locates in front of index i, and from j to i would have sum k. For a lot of subarray problems, we just need to differentiate the dict[sum_i]=**. K-diff Pairs in an Array. For this type of question, it is hard to generalize the types, but I will try my best. for three pointers, the first one is to make sure the starting point. Minimum Window Substring . 37.2%. To optimize, we can use divide and conquer, O(nlgn) vs brute force is O(N²). Otherwise, use two while loop to separate the string into three substrings: left, mid, right. Environment: Python 3.7. (O(nlogn), Brute force searching (recursively O(2^n)), Hash-map (dictionary in Python), can lower the complexity by one power of n, Recursive with memorization (DP, top-down ), Bottom-up with memorization (DP, bottom-up). Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). state: f[i] record the maximum length of increasing subsequence from 0-i. Explore is a well-organized tool that … pattern search problems: sliding window is adopted usually. Explanation: 3 exists in the array, at index=2 and index=5. Note: The length of the input array will not exceed 20,000. Solution: Sort the meetings based on start at first. Number of Longest Increasing Subsequence. Start Exploring. sample problems: search a random target on an array. We want to know the maximum number of operations that we can do following that rule. Solution: use dynamic programming with memo: Cons: it takes too much space, and with LTE. (because the subarray [-1, 2] sums to 1 and is the longest). Given a group of two strings, you need to find the longest uncommon subsequence of this group of two strings. Here we have sum_i, to check if there is a j in front of i that makes sum(j,i)=k, sum(j,i)=sum_i-A Value in Dict = k, so the value need to be sum_i-k, so that we need to check if it is in the dictionary. We define a harmonious array is an array where the difference between its maximum value and its minimum value is exactly 1. Array Problem is given an array, to ask you to meet a certain requirements. 1) The size of the arrays is … Medium. Using state machine to solve complex coding interview questions. Count and print the number of (contiguous) subarrays where the product of all the elements in the subarray is less than k. Example 1: Input: nums = [10, 5, 2, 6], k = 100 Output: 8 Explanation: The 8 subarrays that have product less than 100 are: [10], [5], [2], [6], [10, 5], [5, 2], [2, 6], [5, 2, 6]. Explanation: 3 does not exist in the array, so we return -1. Example 1: Then we try to put them in any group that might fit in. Examples: 122. Also, we can think about divide and conquer. Leetcode Pattern 1 | BFS + DFS == 25% of the problems — part 1 It is amazing how many graph, tree and string problems simply boil down to a DFS (Depth-first search) / … Example 1: Input: array = [1,2,3,4,5,3,1], target = 3. Photo by David Edelstein on Unsplash. Find a certain sum in the list: or a set (Use the elements repeatly), use Dynamic Programming: Sharing methods to solve questions on leetcode, trying to…, CV researcher, ML Engineer @ Facebook AI. If one meeting finishes and another … Recursive (DFS and BFS), divide and conquer (divide into subproblems), curr: used to record current chosen elements. 80. Search Insert Position. For subarray the most important feature is contiguous. or. For the problems that need to sum up subarray, sum(i,j)=sum(0,j)-sum(0,i). Intersection of Two Arrays, 39. Construct Binary Tree from Preorder and Inorder Traversal. 2148 83 Add to List Share. The array nums is complementary if for all indices i (0-indexed), nums[i] + nums[n — 1 — i] equals the same number. In this Leetcode problem, we try to shuffle the numbers in a array in a particular manner.. “Leetcode 1470: Shuffle the array” is published by Pierre-Marie Poitevin. Now let’s get to actual leetcode problems. For example, given array S = [-1, 0, 1, 2, -1, -4], #brute force, use recursive function to write brute force solution. You are given an integer array nums of even length n and an integer limit. Problem 905 : Sort array by parity. 36. Time Complexity: O(kN−kk! Solution: using prefix_sum and hashmap, to just need to reformulate dict[sum_i]. Your are given an array of positive integers nums. I was trying to do the Shuffle the array problem on LeetCode Given an unsorted array of integers, find the length of the longest consecutive elements sequence. Combination Sum Then visit the counter dictionary, to check key+1 and key-1, only when the item is not zero, we can count it as validate, or else it is 0. The longest uncommon subsequence is defined as the longest subsequence of one of these strings and this subsequence should not be any subsequence of the other strings. 106. Return a list of all possible strings we could create. Arrays can be used to store linear data of similar types, but arrays have following limitations. For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray [4,-1,2,1] has the largest sum = 6. i is the start point from [0,len-2], l,r is the other two pointers. Solution: Compared with the last question, this one loose the restriction that need to be continuous. from collections import Counter, defaultdict. leetcode-arrays. Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? If there is no such subarray, return 0 instead. Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn’t one, return 0 instead. LeetCode is the best platform to help you enhance your skills, expand your knowledge and prepare for technical interviews. [2, 3, 6, 7] and target 7, A solution set is: Solution: For this combination, we can use each element one to all possible number of times. Sign up. Output: -1. Solution: the problem is similar to the maximum sum of array with sum==0, so 0=-1, 1==1. ), where NNN is the length of nums, and kkk is as given. Create Account . The first loop is the start number, the second loop is the nums[j]>nums[j-1] or else stop. Merge Two Sorted Lists, Brute force is to get all the element values in a list, sort it and build a LinkedList. Explanation: The array cannot be partitioned into equal sum subsets. It passed 21/15 test cases with TLE. Note: Both the string’s length and k will not exceed 104. If the longest uncommon subsequence doesn’t exist, return -1. Problems. Advantages over arrays 1) Dynamic size 2) Ease of insertion/deletion. The set is like a graph, at the beiginning, we start from 2, the next 3,6,7 are adjacent. dict[0]=-1. Solution: Not thinking about the O(n) complexity, we can use sorting to get [1,2,3,4,100,200], and then use two pointers to get [1,2,3,4]. For e.g., Leetcode Problem … What if we have 6 sum, we can reduce it to O(2N³), what if 8 sum. For the maximum, we can use math and prefix_sum, for the minimum subarray, we use sliding window solution. Max Consecutive Ones II, 485. If these pointers meet at some node then there is a loop. Letter Case Permutation. Remove duplicates: or it is the same to remove certain number 26,27 (in-place). Approach: Sort the given array beforehand and skip over duplicates while backtracking, essentially a simple 2 line change in the previous solution. For example: 784. Best Time to Buy and Sell Stock (keep track of min_price and max_profit, single pass, one transaction), 88. Given an example, strs= “BBCABBBAB”, k=2, when i=0, and j=7, 8–5=3>2, which is at A, we need to shrink it, the maxCharCount changed to 4, i=1, so that 8–1–4=3, i=2, 8–2–3=3, 8–3–3=2, so i=3, current length is 5. Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ≥ s. If there isn’t one, return 0 instead. O(nlogk). Drawbacks: 1) Random access is not allowed. Your algorithm should run in O(n^2) complexity. In this LeetCode problem, we’re given an array of numbers, and a target number, and asked to find the target number in the array (or return -1 if it cannot be found). so for the loop, index i-> sum[i+1]. So, the time complexity is O(2^n). Discuss. This is my attempt to decompose leetcode problems and group them into… In this section, we have maximum subarray and minimum subarray. Typical dp: Using dynamic programming, the difference is we add a count array. For [10,9,2,5,3], the length array is [1,1,1,2,2], for [4,10,4,3,8,9], we have [1, 2, 1, 1, 2, 3]. Medium. Find the length of the longest substring T of a given string (consists of lowercase letters only) such that every character in T appears no less than k times. (curr.push, pop()). If you like the video then please click the thumbs up button and subscribe to my channel. Why Linked List? Find First and Last Position of Element in Sorted Array. DP: Usually, we think of DP when we found current result relies on previous result. Intersections: 349. Solution: Sort the words and then save a set of it to check the parent of it. Two pointers is a superset of the sliding window algorithm, prefix sum too. Here array means one dimension list. Merge Sorted Array, 167. A subsequence is a sequence that can be derived from one sequence by deleting some characters without changing the order of the remaining elements. Once you detect a cycle, think about finding the starting point. In this Leetcode problem, we are given an array nums of integers. It is not a brute-force O(n²) problem. Photo by Dominik Scythe on Unsplash. Credits:Special thanks to @Freezen for adding this problem and creating all test cases. array BFS binary search bit BST combination counting DFS dp easy frequency geometry graph greedy grid hard hashtable heap list math matrix medium O(mn) O(n) Palindrome permutation prefix prefix sum priority queue recursion search shortest path simulation sliding window sort sorting stack string subarray subsequence sum tree two pointers union find xor With memoization: The time complexity is n subproblem, top-down recursive+memo. Note: Length of the array will not exceed 10,000. 76. Solution 1: we have k groups, each time we try to deal with one element from nums, see which group we should put them inside. Follow up: Could you improve it to O(n log n) time complexity? For this question, we need to get the total number of subsubarray, so dict[i] =count, which means every time we just set the dict[i]+=1. Example 1: Input: [3,2,1,5,6,4] and k = 2 Output: 5 Input: [3,2,1,5,6,4] and k = 2 Output: 5 As we skip additional zeroes in groups, naively we will make O(k!)O(k!)O(k!) This video is the solution to Leetcode problem Jump Game. (Brute force, or other algorithms that can be used), Note: If the problem is complex, trying to see the simple version, and then upgrade the simple version to a complex one. Algorithm 1: 1). Here, we definitely will not use sorting. Medium. )O(k^{N-k} k!)O(k​N−k​​k! Solving the Target Sum problem with dynamic programming and more. Sort the list or not at the begin. The input will be two strings, and the output needs to be the length of the longest uncommon subsequence. Given an unsorted array of integers, find the length of longest increasing subsequence. Read writing about Arrays in Leetcode 演算法教學. Now the time complexity is O(n²). Problem Description: Find the kth largest element in an unsorted array.Note that it is the kth largest element in the sorted order, not the kth distinct element. Note: The solution set must not contain duplicate triplets. All integers are in the range of -228 to 228–1 and the result is guaranteed to be at most 231–1. Note: The length of the given binary array will not exceed 50,000. Problem: Given a sorted array nums, remove the duplicates in-place such that each element appears only once and returns the new length.. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.. Clarification: Confused why the returned value is an integer but your answer is an array? Sveta. The longest substring is "aaa", as 'a' is repeated 3 times. If pointers do not meet then linked list doesn’t have loop. To get the BCR, think about the sliding window. T2: Or one starts from the beginning, one from the end and going to the middle (sliding window). Premium Explore Product Developer Sign in. Now, use sliding window, we use a pointer mid, what start from 0, if the whole string satisfy the condition, return len(s). Now, we use dp and bottom-up iterative. For example, the array [1,2,3,4] is complementary … Given an array of integers nums, sort the array in ascending order. Medium. Given an array of positive integers nums and a positive integer target, return the minimal length of a contiguous subarray [nums l, nums l+1, ..., nums r-1, nums r] of which the sum is greater than or equal to target. We can iterate through the array, replace each number with its square. Given an unsorted array of integers, find the number of longest increasing subsequence. The key to solve algorithm problems posed in technical interviews or elsewhere is to quickly identify the underlying patterns. Note: Length of the given array will be not exceed 2000 and the answer is guaranteed to be fit in 32-bit signed int. Maximum Product of Two Elements in an Array” is published by Fatboy Slim. Instead, the pivot point (the point at which the ordering “resets”) is unknown. Here, expert and undiscovered voices alike dive into the heart of any topic and bring new ideas to the surface. 673. So we cannot do binary search with linked lists. More solutions. For the product: we need to record the min_ending_here, for the max_ending_here, can only be [1, +infinity), min_ending_here (-infinity, 1], 674. Solution: Brute force is to use two for loops, first is the starting, second is the end, then we can get the maximum value. Problem Link: Solution Link: Alphabet Board Path: Solution: Combination Sum: Solution: Course Schedule: Solution: Course Schedule II: Solution: Find a Corresponding Node of a Binary Tree in a Clone of That Tree: Solution: Insert into a Binary Search Tree: Solution: K-diff Pairs in an Array… So, at first, put the standard combination algorithm code here: So, we use the backtracking — combination to enumerate all possible subsequence. Given an array of size n, find the majority element. Leetcode: https://leetcode.com/problems/counting-bits/ Problem: Given a non negative integer number num. If there is no answer, return the empty string. Both strings’ lengths will not exceed 100. Unlike arrays, linked list elements are not stored at contiguous location; the elements are linked using pointers. def combinationSum(self, candidates, target): Explanation: The array can be partitioned as [1, 5, 5] and [11]. We can pop out a number in the list, example, 4 , then we use while first-1 to get any number that is on the left side of 4, here it is 3, 2, 1, and use another to find all the bigger one and remove these numbers from the nums array. Longest Continuous Increasing Subsequence. So, it is important to use any(). Explore, If you have a story to tell, knowledge to share, or a perspective to offer — welcome home. calls to search, then an additional O(kN−k)O(k^{N-k})O(k​N−k​​) calls after every element of groups is nonzero. Max Consecutive Ones), (3) Check the special case. Interval problems: sorting and priority queue. (because the subarray [1, -1, 5, -2] sums to 3 and is the longest), Given nums = [-2, -1, 2, 1], k = 1, return 2. If there is more than one possible answer, return the longest word with the smallest lexicographical order. Output: 2. The longest substring is "ababb", as 'a' is repeated 2 times and 'b' is repeated 3 times. Link: Leetcode 1674. note : this first problem … Find the length of a longest substring containing all repeating letters you can get after performing the above operations. LTE. A Systematic Approach to Dynamic Programming, How to answer a coding interview question, A graphical introduction to dynamic programming. For example, Given [100, 4, 200, 1, 3, 2], The longest consecutive elements sequence is [1, 2, 3, 4]. Solution: Should use three pointers, no extra space. Others could be divide and conquer. Find duplicates: Floyd’s Tortoise and Hare algorithm, either linked list or an array : 287, for this type, typically can only find one duplicated element. Medium. Use Arrays… Problem statement The only thing that needs to be done there, apart from squaring the values, is to resort the array, because squaring negative values can reverse the order (for instance [-1, 0, 2] squared will be [1, 0, 4] , and then resorted it will be [0, 1, 4] ). In one move, you can replace any integer from nums with another integer between 1 and limit, inclusive. How about O(n)? 37.0%. Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. Using sliding window technique to solve coding interview questions. A string is represented by an array if the array elements concatenated in order forms the string.. This solution is O(N*N) if the sums are not entirely re … In this section, to get sum we can choose to use hashmap to save the original list so that for the last element, we only check the hashmap, we can lower the complexity by one power of n. However, a better solution is to use two pointers or three pointers. Twitter: @liyinscience, Sharing methods to solve questions on leetcode, trying to systematize different types of questions, Medium is an open platform where 170 million readers come to find insightful and dynamic thinking. For example, given the array [2,3,1,2,4,3] and s = 7, the subarray [4,3] has the minimal length under the problem constraint. Solution: The brute force solution is use two for loops with O(n²). (Usually very important for this type of problems). 105. Learn more, Follow the writers, publications, and topics that matter to you, and you’ll see them on your homepage and in your inbox. Two Sum II — Input array is sorted(t2), 11. Also, generally, the allocated memory is equal to the upper limit irrespective of the usage. Each of the array element will not exceed 100. It is a typical combination problem in recursive functions. Find the contiguous subarray within an array (containing at least one number) which has the largest sum. 2) Extra memory space for a pointer is required with each element of the list. With the constraint, which means the equation needs to be ≤ k. So we can use sliding window to record the max occurence, and when the constraint is violated, we shrink the window. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array. As an added complexity, the array is in ascending order, but not from start to finish. Why Linked List? We have to access elements sequentially starting from the first node. In one operation, we can take any pair of integers adding up to k and take it out of the array. Only letters from a ~ z will appear in input strings. Given an array of integers of size ... (n²) to O(n). T(n) =kT(n-1). Return the minimum index, which is 2. 35. 1) The size of the arrays is fixed: So we must know the upper limit on the number of elements in advance. Remove Duplicates from Sorted Array II. In this series, I am going to solve Leetcode medium problems live with my friend, which you can see on our youtube channel, Today we will do Problem 532. Move one pointer by one and other pointer by two. e.g. Now, given an integer array, you need to find the length of its longest harmonious subsequence among all its possible subsequences. Space Complexity: O(N)O(N)O(N), the space used by recursive calls to search in our call stack. 23. 395. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. It’s easy and free to post your thinking on any topic. l=i+1, r=len-1 at the beignning. For example, Given [[0, 30],[5, 10],[15, 20]], return 2. Example 1: Input: nums = [5,2,3,1] Output: [1,2,3,5] Example 2: Input: nums = [5,1,1,2,0,0] Output: [0,0,1,1,2,5] Constraints: 1 <= nums.length <= 50000-50000 <= nums[i] <= 50000 We can use divide and conquer (see the merge sort) and the priority queue. The difference is here we do not unconditionally use this nums[i] in our result, only if nums[i]>tail, and the final length is the maximum of them all. 34. For this question, we need to get the maximum size of subarray, so dict[i] =min(idx), the earliest that the value appear. Find First and Last Position of Element in Sorted Array. In this Leetcode problem, we are given an array A and are ask to enter the number of subarrays that have a sum of elements divisible by K. Problem statement. (487. To find the rule, T(0)=1, idx, max(memo[i]),0≤inums[i]. Partition Equal Subset Sum, 698. Longest Repeating Character Replacement. Longest Substring with At Least K Repeating Characters. Partition to K Equal Sum Subsets. Python Set; Python List; Python list copy: this is very important, especially if we need to copy a two dimensional list or even higher, use deepcopy() from copy module.

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